Dynamically configured devices simulate multiple controllers with a single DEVICE structure and can have the number of controllers being simulated set by the user. DLI, DZ, DUP, DMC, TDC, VH, DC are all dynamically configured devices.
DLI and TDC are dynamically configured devices which get static bus addresses.
Vector values contained in device information blocks are the true bus relative vector values. CPU specific biased vector values are produced by the respective vector fetching logic and vector values are limited to 9 bits with <1:0> = 0 as specified in both the Unibus and Qbus documents.
VAX 11/.750 Boot ROM code makes non-longword memory references to MassBus and Unibus register space. Minor changes were necessary to allow this behavior which was architecturally undefined behavior, but had real code which depended on it.
Added a BOOTDEV option to the CPU to reflect the 4 position boot device selection switch on real VAX 11/750 hardware.
The UBA750 initial state started with the UBA map registers validly mapping the first 256KB of RAM to Unibus space.
Added simulated PCS/WCS memory which boot code on some operating systems (Ultrix and other BSD derived systems) automatically loaded on the VAX 11/750. PCS/WCS was also automatically loaded by the newer versions of the BOOT ROMs.
Design Notes for Fixing VAX Unaligned Access to IO and Register Space
Problem Statement: VAX unaligned accesses are handled by reading the
surrounding longword (or longwords) and
a) for reads, extracting the addressed addressed word or longword
b) for writes, inserting the addressed word or longword and then
writing the surrounding longword (or longwords) back
This is correct for all memory cases. On the 11/780, the unaligned
access to register or IO space causes an error, as it should. On
CVAX, it causes incorrect behavior, by either performing too many
QBus references, or performing read-modify-writes instead of pure
writes, or accessing the wrong Qbus locations.
The problem cannot be trivially solved with address manipulation.
The core issues is that on CVAX, unaligned access is done to
exactly as many bytes as are required, using a base longword
address and a byte mask. There are five cases, corresponding to
word and longword lengths, and byte offsets 1, 2 (longword only),
and 3. Further, behavior is different for reads and writes, because
the Qbus always performs word operations on reads, leaving it to
the processor to extract a byte if needed.
Conceptual design: Changes in vax_mmu.c:
Unaligned access is done with two separate physical addresses, pa
and pa1, because if the access crosses a page boundary, pa1 may
not be contiguous with pa. It's worth noting that in an unaligned
access, the low part of the data begins at pa (complete with byte
offset), but the high parts begins at pa1 & ~03 (always in the
low-order end of the second longword).
To handle unaligned data, we will add two routines for read and
write unaligned:
data = ReadU (pa, len);
WriteU (pa, len, val);
Note that the length can be 1, 2, or 3 bytes. For ReadU, data is
return right-aligned and masked. For WriteU, val is expected to
be right-aligned and masked.
The read-unaligned flows are changed as follows:
if (mapen && ((off + lnt) > VA_PAGSIZE)) { /* cross page? */
vpn = VA_GETVPN (va + lnt); /* vpn 2nd page */
tbi = VA_GETTBI (vpn);
xpte = (va & VA_S0)? stlb[tbi]: ptlb[tbi]; /* access tlb */
if (((xpte.pte & acc) == 0) || (xpte.tag != vpn) ||
((acc & TLB_WACC) && ((xpte.pte & TLB_M) == 0)))
xpte = fill (va + lnt, lnt, acc, NULL); /* fill if needed */
pa1 = ((xpte.pte & TLB_PFN) | VA_GETOFF (va + 4)) & ~03;
}
else pa1 = ((pa + 4) & PAMASK) & ~03; /* not cross page */
bo = pa & 3;
if (lnt >= L_LONG) { /* lw unaligned? */
sc = bo << 3;
wl = ReadU (pa, L_LONG - bo); /* read both fragments */
wh = ReadU (pa1, bo); /* extract */
return ((wl | (wh << (32 - sc))) & LMASK);
}
else if (bo == 1) /* read within lw */
return ReadU (pa, L_WORD);
else {
wl = ReadU (pa, L_BYTE); /* word cross lw */
wh = ReadU (pa1, L_BYTE); /* read, extract */
return (wl | (wh << 8));
}
These are not very different, but they do reflect that ReadU returns
right-aligned and properly masked data, rather than the encapsulating
longword.
The write-unaligned flows change rather more drastically:
if (mapen && ((off + lnt) > VA_PAGSIZE)) {
vpn = VA_GETVPN (va + 4);
tbi = VA_GETTBI (vpn);
xpte = (va & VA_S0)? stlb[tbi]: ptlb[tbi]; /* access tlb */
if (((xpte.pte & acc) == 0) || (xpte.tag != vpn) ||
((xpte.pte & TLB_M) == 0))
xpte = fill (va + lnt, lnt, acc, NULL);
pa1 = ((xpte.pte & TLB_PFN) | VA_GETOFF (va + 4)) & ~03;
}
else pa1 = ((pa + 4) & PAMASK) & ~03;
bo = pa & 3;
if (lnt >= L_LONG) {
sc = bo << 3;
WriteU (pa, L_LONG - bo, val & insert[L_LONG - bo]);
WriteU (pa, bo, (val >> (32 - sc)) & insert[bo]);
}
else if (bo == 1) /* read within lw */
WriteU (pa, L_WORD, val & WMASK);
else { /* word cross lw */
WriteU (pa, L_BYTE, val & BMASK);
WriteU (pa, L_BYTE, (val >> 8) & BMASK);
}
return;
}
Note that all the burden here has been thrown on the WriteU routine.
-------------
ReadU is the simpler of the two routines that needs to be written.
It will handle memory reads and defer register and IO space to
model-specific unaligned handlers.
int32 ReadU (uint32 pa, int32 lnt)
{
int32 dat;
int32 sc = (pa & 3) << 3;
if (ADDR_IS_MEM (pa))
dat = M[pa >> 2];
else {
mchk = REF_V;
if (ADDR_IS_IO (pa))
dat = ReadIOU (pa, lnt);
else dat = ReadRegU (pa, lnt);
}
return ((dat >> sc) & insert[lnt]);
}
Note that the ReadIOU and ReadRegU return a "full longword," just
like their aligned counterparts, and ReadU right-aligns the result,
just as ReadB, ReadW, and ReadL do.
WriteU must handle the memory read-modify-write sequence. However,
it defers register and IO space to model-specific unaligned handlers.
void WriteU (uint32 pa, int32 lnt, int32 val)
{
if (ADDR_IS_MEM (pa)) {
int32 bo = pa & 3;
int32 sc = bo << 3;
M[pa >> 2] = (M[pa >> 2] & ~(insert[len] << sc) | (val << sc);
}
else if ADDR_IS_IO (pa)
WriteIOU (pa, lnt, val);
else WriteRegU (pa, lnt, val);
return;
}
--------------
For the 11/780, ReadIOU, ReadRegU, WriteIOU, and WriteRegU all do the
same thing: they throw an SBI machine check. We can write explicit
routines to do this (and remove the unaligned checks from all the
normal adapter flows), or leave things as they are and simply define
the four routines as macros that go to the normal routines. So there's
very little to do.
On CVAX, I suspect that ReadRegU and WriteRegU behave like the
normal routines. The CVAX specs don't say much, but CMCTL (the memory
controller) notes that it ignores the byte mask and treats every
access as an aligned longword access. I suspect this is true for
the other CVAX support chips, but I no longer have chip specs.
The Qbus, on the other hand... that's a fun one. Note that all of
these cases are presented to the existing aligned IO routine:
bo = 0, byte, word, or longword length
bo = 2, word
bo = 1, 2, 3, byte length
All the other cases are going to end up at ReadIOU and WriteIOU,
and they must turn the request into the exactly correct number of
Qbus accesses AND NO MORE, because Qbus reads can have side-effects,
and word read-modify-write is NOT the same as a byte write.
The read cases are:
bo = 0, byte or word - read one word
bo = 1, byte - read one word
bo = 2, byte or word - read one word
bo = 3, byte - read one word
bo = 0, triword - read two words
bo = 1, word or triword - read two words
ReadIOU is very similar to the existing ReadIO:
int32 ReadIOU (uint32 pa, int32 lnt)
{
int32 iod;
iod = ReadQb (pa); /* wd from Qbus */
if ((lnt + (pa & 1)) <= 2) /* byte or word & even */
iod = iod << ((pa & 2)? 16: 0); /* one op */
else iod = (ReadQb (pa + 2) << 16) | iod; /* two ops, get 2nd wd */
SET_IRQL;
return iod;
}
The write cases are:
bo = x, lnt = byte - write one byte
bo = 0 or 2, lnt = word - write one word
bo = 1, lnt = word - write two bytes
bo = 0, lnt = triword - write word, byte
bo = 1, lnt = triword - write byte, word
WriteIOU is similar to the existing WriteIO:
void WriteIO (uint32 pa, int32 val, int32 lnt)
{
switch (lnt) {
case L_BYTE: /* byte */
WriteQb (pa, val & BMASK, WRITEB);
break;
case L_WORD: /* word */
if (pa & 1) { /* odd addr? */
WriteQb (pa, val & BMASK, WRITEB);
WriteQb (pa + 1, (val >> 8) & BMASK, WRITEB);
}
else WriteQb (pa, val, WRITE);
break;
case 3: /* triword */
if (pa & 1) { /* odd addr? */
WriteQb (pa, val & BMASK, WRITEB);
WriteQb (pa + 1, (val >> 8) & WMASK, WRITE);
}
else {
WriteQb (pa, val & WMASK, WRITE);
WriteQb (pa + 2, (val >> 16) & BMASK, WRITEB);
}
break;
}
SET_IRQL;
return;
}
-----------------
I think this handles all the cases.
/Bob Supnik
Conflicts:
VAX/vax780_defs.h
VAX/vax_mmu.c
VAX/vaxmod_defs.h
Show IOSPACE doesn't always get the number of devices right due to device creativity.
o The distinction between UNIT and DEVICE has blurred
o MUX devices merge several physical devices into one device/unit
o Dynamic device sizing has made things more volatile.
This edit solves the problem for SHOW IOSPACE by adding an (optional) word to the DIBs.
The word contains the amount of IO space consumed by each instance of the physical device that's being emulated.
E.G., if it's a DZ11, the device is the DZ11 module, or 8 lines, even though the MUX device may support 32.
This enables SHOW IOSPACE to determine the number of physical devices being emulated, which is what folks need when configuring software. The word may have other uses - in a generic dynamic device sizing routine - which is why the amount of IOSPACE per device was chosen rather than the 'number of physical devices.'
The edit should not make any existing device regress. If the new word (ulnt) is zero (not initialized), SHOW IOSPACE will default to the number of units in the device, or if there's no device (CPUs), 1 as before. If it is present, the number of devices is the calculated as total allocation/allocation-per-device.
The edit updates all the devices that seem to require this treatment, and all the processors that define the UNIBUS/QBUS DIBs.
The actual machine can have a max to 260MB of memory.
There are three different memory boards that exists for the 86x0, from a software point of view.
4MB, 16MB, and 64MB. In addition, you can mix different boards.
The rule is to put large boards first, and smaller boards later.
Even more fun is the fact that the 16MB and 64MB boards are stacked and thus take up two backplane slots in the backplane, while the 4MB board only takes up one slot.
To complete the picture, there are 8 slots in the memory backplane. You start by putting boards in slot 1, going to slot 8. The boards taking up two slots actually use slot n, while covering slot n-1. That means that the board in slot 1 does not cover up any other slot.
If you are using 16MB boards, the max memory is 68MB.
Slot 1,3,5 and 7 will have 16MB boards. And then you can place a 4MB board in slot 8.
Same story with the 64MB boards.
